You need to find the maximum value of len(u, v) ⋅ gcd(u, v) l e n (u, v) g c d (u, v) over all pairs of vertices in the tree. Each test consists of multiple test cases. The first line contains a single …

Type Tags Community Tag Rating ( 147 ) G Optimizations From Chelsu PROGRAMMING divide and conquer dp number theory trees Add tag

Oct 3, 2025 · CF1916G Optimizations From Chelsu 点分治，假设路径的端点是 s 和 t，那么 l e n × g 就是 (d s + d t) × gcd (v s, v t)，其中 d 是到根链长度， v 是到根的 gcd。

考虑一个非常神奇的想法，设点分治的分治重心为 rt，先只求出所有 len (rt,u)\times \gcd (rt,u) 的最大值，设其为 mx。 显然最优解是两条链的拼接，不如设拼接的两条链的 len,\gcd 分别是 …

codeforces#P1916G. Optimizations From Chelsu. You are given a tree with n n vertices, whose vertices are numbered from 1 1 to n n. Each edge is labeled with some integer w i wi.

Jul 18, 2024 · Providing alternative solutions or optimizations. Correcting errors or improving code readability. Adding solutions to problems that are not yet covered. Your feedback is valuable! If …

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